Q1 A man walks 3 km north, then 4 km east. How far is he from his starting point?
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5 km.
The two legs are at right angles, so the direct distance is √(3² + 4²) = √25 = 5 km. He is north-east of where he began.
These are coordinate geometry dressed up as a walk. Put north at the top of your sheet, draw each leg, and the final answer is almost always a right-angled triangle between the start and the end.
The one thing to be careful about is turns: "turns left" is relative to the direction the person is currently facing, not to the page.
Try each one before opening the answer. A solution you have read is not a solution you can produce under time pressure, which is the only kind that counts.
Q1 A man walks 3 km north, then 4 km east. How far is he from his starting point?
5 km.
The two legs are at right angles, so the direct distance is √(3² + 4²) = √25 = 5 km. He is north-east of where he began.
Q2 Walking 10 m south, then 6 m west, then 10 m north, then 6 m east: where does he end up?
Back at the start.
Add the legs by axis. North-south: 10 south and 10 north cancel. East-west: 6 west and 6 east cancel. Both totals are zero, so the displacement is zero - he has walked a rectangle.
Q3 Facing north, a man turns right, walks 5 km, turns right again and walks 12 km. How far is he from the start, and in which direction?
13 km, south-east.
Facing north and turning right makes him face east; he walks 5 km east. Turning right again makes him face south; he walks 12 km south. The distance is √(5² + 12²) = 13 km, and he is east and south of the start.